So instead of using V BB in calculations, you would just use V CC instead. V CE= V CC - I C x R C= 15v - (7.68mA x 1KΩ)= 7.32vīase bias can also be done with a single supply voltage, V CC, with V BB omitted. With I C then known, the collector-emitter voltage, V CE can be calculated. The collector current I C can be calculated next: Since the voltage drop across a silicon junction is 0.7V, the value of V BE=0.7V. The base current can be found by dividing the voltage across resistor R B by the value of The first calculation we will make is for the base current I B. Or else, it's impossible to tell whether the voltage and current values are correct or not. When using any biasing technique, calculations must be made of the various voltages and currents through a BJT So the total output current, I C will be I C=β dc x I B. β dc is the amplification factor by which the base current getsĪmplified by. Using the base biasing method, the collector current I C is dependent only on the values of The collector resistor, R C provides the desired voltage in the collector circuit.
This voltage, reverse-biases the transistor, so that the transistor has sufficient power to have an amplified outputĬollector current. V CC is the collector supply voltage, which is required for a transistor to have sufficient power R B is a resistance value that is used to provide the desired value of base current Iī. V BB is the base supply voltage, which is used to give the transistor sufficient current to V BB, is the correct voltage, which then supplies the correct current so that the BJT has enough base current toīelow is a typical BJT receiving base bias: Base bias ensures that the voltage fed to the base, Therefore, it's very important that a transistor is biased correctly for it to produceīase bias the simplest way to bias a BJT transistor. Produce clipping of the signal or produce too low of gain. Without appropriate transistor biasing, the transistor may not function at all or amplify very poorly, such as
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